TS7044
Parameter 'a' implicitly has an 'any' type, but a better type may be inferred from usage.
Broken Code ❌
const multiply = (a, b) => a * b;Fixed Code ✔️
From the body of the arrow function expression, TypeScript can see by the * that a and b may be of type number:
const multiply = (a: number, b: number) => a * b;