TypeScript TV

TS17009

'super' must be called before accessing 'this' in the constructor of a derived class.

Broken Code ❌

abstract class Animal {
  abstract name: string;
}
 
class Dog extends Animal {
  public name;
 
  constructor(name: string) {
    this.name = name;
    super();
  }
}

Fixed Code ✔️

abstract class Animal {
  abstract name: string;
}
 
class Dog extends Animal {
  public name;
 
  constructor(name: string) {
    super();
    this.name = name;
  }
}